1. **State the problem:** We need to find the area and perimeter of an irregular polygon drawn on a grid where each square measures 2 cm by 2 cm. 2. **Understand the grid and shape:** Each small square has an area of $$2 \text{ cm} \times 2 \text{ cm} = 4 \text{ cm}^2$$. 3. **Count the squares for area:** Count the full squares inside the polygon and estimate partial squares if any. 4. **Calculate area:** Multiply the number of full squares by 4 cm² and add the estimated area of partial squares. 5. **Calculate perimeter:** Count the length of all outer edges of the polygon. Each edge corresponds to the side of a square, which is 2 cm. 6. **Sum the lengths of all edges to get the perimeter.** Since the shape is cross-like and formed by 5 squares (one center and four arms), the area is $$5 \times 4 = 20 \text{ cm}^2$$. The perimeter consists of 12 edges of length 2 cm each, so perimeter is $$12 \times 2 = 24 \text{ cm}$$. **Final answers:** - Area = $$20 \text{ cm}^2$$ - Perimeter = $$24 \text{ cm}$$