1. The problem asks to draw a flat shape whose area equals its perimeter. 2. Let's consider a square with side length $s$. 3. The area $A$ of the square is given by the formula: $$A = s^2$$ 4. The perimeter $P$ of the square is given by: $$P = 4s$$ 5. We want the area to be equal to the perimeter, so set: $$s^2 = 4s$$ 6. Solve for $s$: $$s^2 - 4s = 0$$ $$s(s - 4) = 0$$ 7. The solutions are $s = 0$ (not valid for a shape) or $s = 4$. 8. Therefore, a square with side length $4$ units has area and perimeter both equal to $16$. 9. This satisfies the condition that the area equals the perimeter. 10. You can draw a square with side length $4$ units to represent this shape. Final answer: A square with side length $4$ units has area and perimeter both equal to $16$.