1. **Problem statement:** Calculate the area and perimeter of each given polygon.
---
### a) Rectangle (12 cm × 6 cm)
1. Formula for area: $$A = \text{length} \times \text{width}$$
2. Formula for perimeter: $$P = 2 \times (\text{length} + \text{width})$$
3. Calculate area: $$A = 12 \times 6 = 72$$ cm²
4. Calculate perimeter: $$P = 2 \times (12 + 6) = 2 \times 18 = 36$$ cm
---
### b) Rhombus (diagonals 8 cm and 4 cm, side length 4.5 cm)
1. Formula for area of rhombus: $$A = \frac{d_1 \times d_2}{2}$$ where $d_1$ and $d_2$ are diagonals
2. Formula for perimeter: $$P = 4 \times \text{side}$$
3. Calculate area: $$A = \frac{8 \times 4}{2} = \frac{32}{2} = 16$$ cm²
4. Calculate perimeter: $$P = 4 \times 4.5 = 18$$ cm
---
### c) Parallelogram (base 9 cm, side 17 cm, height 12 cm)
1. Formula for area: $$A = \text{base} \times \text{height}$$
2. Formula for perimeter: $$P = 2 \times (\text{base} + \text{side})$$
3. Calculate area: $$A = 9 \times 12 = 108$$ cm²
4. Calculate perimeter: $$P = 2 \times (9 + 17) = 2 \times 26 = 52$$ cm
---
### d) Pentagon (sides: 25 cm, 14 cm, 20.5 cm, 42.5 cm, interior dashed length 18 cm)
1. Since no height or apothem is given, and the shape is irregular, we approximate perimeter by summing all sides.
2. Perimeter: $$P = 25 + 14 + 20.5 + 42.5 + 18 = 120$$ cm
3. Area is not directly computable with given data; no height or apothem provided.
---
### e) Triangle (base 8 cm, sides 20 cm and 11 cm, height 3 cm)
1. Formula for area: $$A = \frac{1}{2} \times \text{base} \times \text{height}$$
2. Formula for perimeter: $$P = \text{side}_1 + \text{side}_2 + \text{base}$$
3. Calculate area: $$A = \frac{1}{2} \times 8 \times 3 = 12$$ cm²
4. Calculate perimeter: $$P = 20 + 11 + 8 = 39$$ cm
---
### f) Triangle (left side 9 cm, base 18 cm, slanted side 20 cm)
1. No height given, so area calculation requires Heron's formula.
2. Calculate semi-perimeter: $$s = \frac{9 + 18 + 20}{2} = \frac{47}{2} = 23.5$$ cm
3. Heron's formula for area: $$A = \sqrt{s(s - a)(s - b)(s - c)}$$
4. Calculate area:
$$A = \sqrt{23.5(23.5 - 9)(23.5 - 18)(23.5 - 20)} = \sqrt{23.5 \times 14.5 \times 5.5 \times 3.5}$$
5. Calculate inside the root:
$$23.5 \times 14.5 = 340.75$$
$$5.5 \times 3.5 = 19.25$$
$$340.75 \times 19.25 = 6554.9375$$
6. Area: $$A = \sqrt{6554.9375} \approx 81$$ cm²
7. Perimeter: $$P = 9 + 18 + 20 = 47$$ cm
---
### g) Kite (horizontal diagonal 37 cm, vertical diagonal 24 cm, side lengths 17 cm and 28 cm)
1. Formula for area of kite: $$A = \frac{d_1 \times d_2}{2}$$
2. Formula for perimeter: $$P = 2 \times (\text{side}_1 + \text{side}_2)$$
3. Calculate area: $$A = \frac{37 \times 24}{2} = \frac{888}{2} = 444$$ cm²
4. Calculate perimeter: $$P = 2 \times (17 + 28) = 2 \times 45 = 90$$ cm
---
**Final answers:**
- a) Area = 72 cm², Perimeter = 36 cm
- b) Area = 16 cm², Perimeter = 18 cm
- c) Area = 108 cm², Perimeter = 52 cm
- d) Perimeter = 120 cm (area not computable with given data)
- e) Area = 12 cm², Perimeter = 39 cm
- f) Area ≈ 81 cm², Perimeter = 47 cm
- g) Area = 444 cm², Perimeter = 90 cm
Area Perimeter Polygons 3B581B
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.