1. **State the problem:** We have a rectangle with length 32 cm and width 14 cm. Two semicircles, each with diameter 14 cm, are cut out from the shorter sides. We need to find the area of the paper that remains. 2. **Formula for area of rectangle:** $$\text{Area}_{rectangle} = \text{length} \times \text{width}$$ 3. **Formula for area of a circle:** $$\text{Area}_{circle} = \pi r^2$$ Since each semicircle has diameter 14 cm, radius $r = \frac{14}{2} = 7$ cm. 4. **Calculate the area of the rectangle:** $$32 \times 14 = 448 \text{ cm}^2$$ 5. **Calculate the area of one semicircle:** $$\frac{1}{2} \times 3.14 \times 7^2 = \frac{1}{2} \times 3.14 \times 49 = \frac{1}{2} \times 153.86 = 76.93 \text{ cm}^2$$ 6. **Calculate the total area of two semicircles:** $$2 \times 76.93 = 153.86 \text{ cm}^2$$ 7. **Calculate the remaining area:** $$448 - 153.86 = 294.14 \text{ cm}^2$$ **Final answer:** The area of the paper that remains is **294.14 cm²**.