1. **State the problem:** We need to find the area of ring B in a target made of two rings and one circle, all sharing the same center. Ring B is the blue ring with an outer radius of 13 cm and an inner radius equal to the radius of the smaller circle A, which is 4 cm. 2. **Formula used:** The area of a ring (annulus) is the difference between the areas of two circles: the larger circle minus the smaller circle. $$\text{Area of ring} = \pi R^2 - \pi r^2 = \pi (R^2 - r^2)$$ where $R$ is the outer radius and $r$ is the inner radius. 3. **Apply the formula:** For ring B, $R = 13$ cm and $r = 4$ cm. $$\text{Area of ring B} = \pi (13^2 - 4^2) = \pi (169 - 16) = \pi \times 153$$ 4. **Calculate the numerical value:** Using $\pi \approx 3.1416$, $$\text{Area of ring B} \approx 3.1416 \times 153 = 480.4428$$ 5. **Round to 1 decimal place:** $$480.4$$ **Final answer:** The area of ring B is $480.4$ square centimeters.