1. **Stating the problem:** Calculate the area of the shape described in Question 11 with dimensions 8 mm, 2 mm, and 17 mm. 2. **Understanding the shape:** The shape has a curved top middle section with horizontal length 17 mm, height 8 mm, and curve width 2 mm. 3. **Formula and approach:** We can consider the shape as a rectangle minus a semicircular cut or addition depending on the description. 4. **Calculate the rectangle area:** $$\text{Area}_{rectangle} = \text{length} \times \text{height} = 17 \times 8 = 136 \text{ mm}^2$$ 5. **Calculate the semicircle area:** Radius $r = \frac{2}{2} = 1$ mm $$\text{Area}_{semicircle} = \frac{1}{2} \pi r^2 = \frac{1}{2} \pi (1)^2 = \frac{\pi}{2} \approx 1.5708 \text{ mm}^2$$ 6. **Final area calculation:** Assuming the semicircle is a cut-out, $$\text{Area}_{shape} = 136 - 1.5708 = 134.4292 \text{ mm}^2$$ 7. **Answer:** The area of the shape is approximately $134.43$ mm$^2$.