1. **State the problem:** We need to find the area of a shape composed of a square and a semicircle, both with side/radius length 6 cm. 2. **Formula for area of square:** The area of a square is given by $$A_{square} = s^2$$ where $s$ is the side length. 3. **Formula for area of semicircle:** The area of a semicircle is half the area of a full circle, so $$A_{semicircle} = \frac{1}{2} \pi r^2$$ where $r$ is the radius. 4. **Calculate the area of the square:** $$A_{square} = 6^2 = 36 \text{ cm}^2$$ 5. **Calculate the area of the semicircle:** $$A_{semicircle} = \frac{1}{2} \pi (6)^2 = \frac{1}{2} \pi 36 = 18\pi \text{ cm}^2$$ 6. **Calculate total area:** $$A_{total} = A_{square} + A_{semicircle} = 36 + 18\pi$$ 7. **Approximate using $\pi \approx 3.1416$:** $$A_{total} \approx 36 + 18 \times 3.1416 = 36 + 56.5488 = 92.5488 \text{ cm}^2$$ 8. **Round to nearest 0.1 cm²:** $$\boxed{92.5 \text{ cm}^2}$$