1. **State the problem:** We need to find the area of a figure composed of a square with side length 8 and four semicircles attached to each side, each with diameter 8. 2. **Formula and explanation:** - Area of the square: $A_{square} = s^2$ where $s$ is the side length. - Area of a circle: $A_{circle} = \pi r^2$ where $r$ is the radius. - Each semicircle has radius $r = \frac{8}{2} = 4$. - Four semicircles together make two full circles (since $4 \times \frac{1}{2} = 2$). 3. **Calculate the area of the square:** $$A_{square} = 8^2 = 64$$ 4. **Calculate the area of the four semicircles combined:** $$A_{semicircles} = 2 \times \pi \times 4^2 = 2 \times \pi \times 16 = 32\pi$$ 5. **Total area of the figure:** $$A_{total} = A_{square} + A_{semicircles} = 64 + 32\pi$$ 6. **Approximate the value:** $$A_{total} \approx 64 + 32 \times 3.1416 = 64 + 100.5312 = 164.5312$$ Rounded to the nearest tenth: $$164.5$$ **Final answer:** The area of the figure is approximately $164.5$ square units.