Subjects geometry

Basketball Court Diagonal 1A2C94

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1. **Problem Statement:** Find the length of the diagonal of a basketball court that is 94 feet long and 50 feet wide. 2. **Formula:** Use the Pythagorean Theorem: $$a^2 + b^2 = c^2$$ where $a$ and $b$ are the legs of the right triangle (length and width), and $c$ is the diagonal. 3. **Substitute values:** $$94^2 + 50^2 = c^2$$ 4. **Calculate squares:** $$8836 + 2500 = c^2$$ 5. **Add:** $$11336 = c^2$$ 6. **Solve for $c$:** $$c = \sqrt{11336}$$ 7. **Calculate square root:** $$c \approx 106.4$$ 8. **Answer:** The length of the diagonal of the basketball court is approximately 106.4 feet. **Explanation:** We used the Pythagorean Theorem because the diagonal forms a right triangle with the length and width of the court. By squaring the length and width, adding them, and then taking the square root, we find the diagonal length.
94 ftDiagonal50 ft