1. **Problem Statement:**
We have two bearings from the north direction: 135° and 060°, with distances 8 km and 15 km respectively. We want to find the relative position of the two points described by these bearings and distances.
2. **Understanding Bearings:**
Bearings are measured clockwise from the north direction.
- Bearing 135° means the point is located southeast.
- Bearing 060° means the point is located northeast.
3. **Convert Bearings to Cartesian Coordinates:**
We use the formulas:
$$x = d \times \sin(\theta)$$
$$y = d \times \cos(\theta)$$
where $d$ is the distance and $\theta$ is the bearing angle.
4. **Calculate Coordinates for Each Point:**
- For bearing 135° and distance 8 km:
$$x_1 = 8 \times \sin(135^\circ) = 8 \times \frac{\sqrt{2}}{2} = 8 \times 0.7071 = 5.657$$
$$y_1 = 8 \times \cos(135^\circ) = 8 \times -\frac{\sqrt{2}}{2} = 8 \times -0.7071 = -5.657$$
- For bearing 060° and distance 15 km:
$$x_2 = 15 \times \sin(60^\circ) = 15 \times \frac{\sqrt{3}}{2} = 15 \times 0.8660 = 12.990$$
$$y_2 = 15 \times \cos(60^\circ) = 15 \times \frac{1}{2} = 7.5$$
5. **Interpretation:**
- Point 1 is at approximately $(5.657, -5.657)$ km.
- Point 2 is at approximately $(12.990, 7.5)$ km.
6. **Summary:**
Using the bearings and distances, we converted polar coordinates to Cartesian coordinates to find the relative positions of the two points from the origin (north direction).
**Final coordinates:**
- Point 1: $(5.657, -5.657)$ km
- Point 2: $(12.990, 7.5)$ km
Bearing Coordinates E5B83D
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.