1. **State the problem:** A bicycle tire has a diameter of 22 inches. We want to find how many feet the bicycle travels when the wheel makes 20 revolutions, rounding to the nearest hundredth of a foot. 2. **Formula used:** The distance traveled by the bicycle is the circumference of the wheel times the number of revolutions. The circumference $C$ of a circle is given by: $$C = \pi \times d$$ where $d$ is the diameter. 3. **Calculate the circumference:** $$C = \pi \times 22 = 22\pi \text{ inches}$$ 4. **Calculate total distance in inches:** $$\text{Distance} = 20 \times 22\pi = 440\pi \text{ inches}$$ 5. **Convert inches to feet:** Since 12 inches = 1 foot, $$\text{Distance in feet} = \frac{440\pi}{12} = \frac{\cancel{440}\pi}{\cancel{12}} = \frac{110\pi}{3} \approx 115.19 \text{ feet}$$ 6. **Final answer:** The bicycle travels approximately **115.19 feet** after 20 revolutions.