1. **State the problem:** Jaxon has two boxes. The first box has dimensions length = 24 inches, width = 12 inches, and height = 10 inches. The second box keeps the same length and width but reduces the height to one-third of the original height. We need to find how the volume of the second box compares to the first box. 2. **Formula for volume of a rectangular box:** $$\text{Volume} = \text{length} \times \text{width} \times \text{height}$$ 3. **Calculate the volume of the first box:** $$V_1 = 24 \times 12 \times 10 = 2880$$ cubic inches. 4. **Calculate the height of the second box:** $$\text{height}_2 = \frac{1}{3} \times 10 = \frac{10}{3}$$ inches. 5. **Calculate the volume of the second box:** $$V_2 = 24 \times 12 \times \frac{10}{3}$$ 6. **Simplify the volume of the second box:** $$V_2 = 24 \times 12 \times \frac{10}{3} = 24 \times 12 \times \cancel{\frac{10}{3}}$$ $$= 24 \times 12 \times \frac{10}{3} = 24 \times 12 \times \frac{10}{3}$$ Calculate step by step: $$24 \times 12 = 288$$ $$288 \times \frac{10}{3} = 288 \times \frac{10}{3}$$ Divide 288 by 3: $$\cancel{288} \div 3 = 96$$ Multiply by 10: $$96 \times 10 = 960$$ cubic inches. 7. **Compare volumes:** $$\frac{V_2}{V_1} = \frac{960}{2880} = \frac{1}{3}$$ **Answer:** The volume of the second box is one-third of the volume of the first box. **How to solve on a calculator:** - Calculate the volume of the first box: enter 24 × 12 × 10 = 2880. - Calculate the height of the second box: 10 ÷ 3 = 3.333... - Calculate the volume of the second box: 24 × 12 × 3.333... = 960. - Divide the second volume by the first volume: 960 ÷ 2880 = 0.333..., which is one-third.