1. **State the problem:** Raymond has a piece of wrapping paper that measures 1 m by 1 m, which is 100 cm by 100 cm, so the total area of the paper is $100 \times 100 = 10000$ cm$^2$. He needs to wrap a box with dimensions 40 cm by 35 cm by 45 cm. We need to find the surface area of the box to determine if the wrapping paper is enough. 2. **Formula for surface area of a rectangular prism:** $$SA = 2(lw) + 2(lh) + 2(wh)$$ where $l$, $w$, and $h$ are the length, width, and height of the box. 3. **Calculate the surface area:** Given $l=40$ cm, $w=35$ cm, and $h=45$ cm, $$SA = 2(40 \times 35) + 2(40 \times 45) + 2(35 \times 45)$$ Calculate each term: $$2(1400) + 2(1800) + 2(1575) = 2800 + 3600 + 3150$$ Sum these: $$SA = 2800 + 3600 + 3150 = 9550 \text{ cm}^2$$ 4. **Compare surface area with wrapping paper area:** Wrapping paper area = $10000$ cm$^2$ Box surface area = $9550$ cm$^2$ Since $9550 < 10000$, Raymond has enough wrapping paper to cover the box. **Final answer:** Yes, Raymond has enough paper to wrap the box because the surface area of the box ($9550$ cm$^2$) is less than the area of the wrapping paper ($10000$ cm$^2$).