1. **State the problem:** We need to find the distance between diagonally opposite corners of a rectangular brick wall that is 6 m wide and 1 m tall. 2. **Formula used:** We use Pythagoras' theorem, which states that in a right triangle, the square of the hypotenuse ($c$) is equal to the sum of the squares of the other two sides ($a$ and $b$): $$c^2 = a^2 + b^2$$ 3. **Identify the sides:** Here, the width $a = 6$ m and the height $b = 1$ m. 4. **Calculate the hypotenuse:** $$c = \sqrt{6^2 + 1^2} = \sqrt{36 + 1} = \sqrt{37}$$ 5. **Evaluate the square root:** $$c \approx 6.0827$$ 6. **Round to 1 decimal place:** $$c \approx 6.1$$ **Final answer:** The distance between diagonally opposite corners is approximately $6.1$ m.