Subjects geometry

Capsule Area 59F2C3

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1. **Stating the problem:** We are given a vertical capsule (obround) shape with a total height of 17 m and a width of 15 m. The shape consists of two semicircles (top and bottom) connected by two vertical straight sides. 2. **Goal:** Calculate the area of this capsule shape. 3. **Formula used:** The area of a capsule (obround) is the sum of the area of the rectangle between the semicircles and the areas of the two semicircles. $$\text{Area} = \text{Area of rectangle} + \text{Area of two semicircles}$$ 4. **Important rules:** - The height of the rectangle is the total height minus the diameters of the two semicircles. - The width of the rectangle equals the diameter of the semicircles. - The radius $r$ of each semicircle is half the width. 5. **Calculate radius:** $$r = \frac{15}{2} = 7.5\,m$$ 6. **Calculate height of rectangle:** $$\text{Height of rectangle} = 17 - 2 \times 7.5 = 17 - 15 = 2\,m$$ 7. **Calculate area of rectangle:** $$\text{Area}_{rectangle} = \text{width} \times \text{height} = 15 \times 2 = 30\,m^2$$ 8. **Calculate area of two semicircles (which is one full circle):** $$\text{Area}_{circles} = \pi r^2 = \pi \times 7.5^2 = \pi \times 56.25 = 56.25\pi\,m^2$$ 9. **Calculate total area:** $$\text{Area}_{total} = 30 + 56.25\pi \approx 30 + 176.71 = 206.71\,m^2$$ 10. **Final answer:** The area of the capsule shape is approximately **206.71 square meters**.
15 m17 m