Subjects geometry

Chocolate Bricks B1495E

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1. **Problem:** Calculate the perimeter when 5 chocolate bricks, each 10 cm long and 4 cm wide, are connected horizontally. 2. **Formula:** The perimeter $P$ of a rectangle is $P=2(\text{length} + \text{width})$. 3. **Important rule:** When connecting rectangles side by side horizontally, the total length is the sum of all lengths minus the overlapping sides, and the width remains the same. 4. **Work:** - Each brick length = 10 cm, width = 4 cm - For 5 bricks connected horizontally, total length = $10 \times 5 = 50$ cm - But the bricks share sides where they connect, so the total width is still 4 cm - The perimeter is calculated as: $$P = 2(\text{total length} + \text{width}) = 2(50 + 4) = 2 \times 54 = 108$$ cm 5. **Answer:** The perimeter of 5 connected chocolate bricks is **108 cm**.