1. **Problem:** Find the values of $x$ and $y$ where $O$ is the center of the circle and angles satisfy $AO0 + 108 + COD + 4AO8 = 360^6$.
**Step 1:** Understand that the sum of angles around point $O$ is $360^6$.
**Step 2:** Given angles are $AO0 = 35^6$, $108^6$, $COD = y$, and $4AO8 = 35^6$.
**Step 3:** Write the equation:
$$35 + 108 + y + 35 = 360$$
**Step 4:** Simplify:
$$178 + y = 360$$
**Step 5:** Solve for $y$:
$$y = 360 - 178 = 182^6$$
**Step 6:** Since $x$ is not explicitly given, assume $x = 35^6$ as per the given angles.
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2. **Problem:** In cyclic quadrilateral $ABCD$ with $AB$ as diameter and $9ADC = 140^6$, find $9BAC$.
**Step 1:** Recall that angle subtended by diameter is $90^6$.
**Step 2:** Use the property of cyclic quadrilateral: opposite angles sum to $180^6$.
**Step 3:** Since $9ADC = 140^6$, then $9ABC = 40^6$ (because $180 - 140 = 40$).
**Step 4:** Triangle $ABC$ is right angled at $C$ because $AB$ is diameter, so $9BAC + 9BCA = 90^6$.
**Step 5:** Since $9BCA = 40^6$, then
$$9BAC = 90 - 40 = 50^6$$
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3. **Problem:** Given $OA = 5$ cm, $AB = 8$ cm, and $OD ot AB$, find length $CD$.
**Step 1:** Since $O$ is center and $OA = 5$ cm, $OB = 5$ cm (radius).
**Step 2:** $AB = 8$ cm, so midpoint $D$ of $AB$ is at $4$ cm from $A$.
**Step 3:** $OD$ is perpendicular from center to chord $AB$, so $OD$ bisects $AB$.
**Step 4:** Use Pythagoras theorem in triangle $OAD$:
$$OD = \sqrt{OA^2 - AD^2} = \sqrt{5^2 - 4^2} = \sqrt{25 - 16} = 3$$ cm
**Step 5:** $CD$ is the length from $C$ to $D$. Without coordinates or more info, assume $C$ lies on circle such that $CD$ is chord length. More info needed to solve $CD$.
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4. **Problem:** Two congruent circles with centers $O$ and $O'$ intersect at points $A$ and $B$. Is $9AOB = 9AO'B$ true?
**Step 1:** Since circles are congruent and intersect at $A$ and $B$, arcs $AB$ in both circles are equal.
**Step 2:** Angles $9AOB$ and $9AO'B$ are central angles subtending the same chord $AB$ in congruent circles.
**Step 3:** Therefore, $9AOB = 9AO'B$. The statement is true.
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**Final answers:**
1. $x = 35^6$, $y = 182^6$
2. $9BAC = 50^6$
3. $OD = 3$ cm; $CD$ cannot be determined with given data
4. Statement is true: $9AOB = 9AO'B$
Circle Angles 10E5C5
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