1. **Problem 1:** Calculate the size of angle $x$ in the cyclic quadrilateral $ABEC$ where angle $D$ is $136^\circ$.
2. **Key fact:** Opposite angles in a cyclic quadrilateral sum to $180^\circ$.
3. Since $ABEC$ is cyclic, angles $x$ (at $A$) and $136^\circ$ (at $D$) are opposite angles.
4. Use the formula:
$$x + 136^\circ = 180^\circ$$
5. Solve for $x$:
$$x = 180^\circ - 136^\circ = 44^\circ$$
6. **Reason:** Opposite angles of a cyclic quadrilateral are supplementary.
7. **Problem 2:** Work out the size of angle $\theta$ at point $C$ formed by tangent $BC$ and line $DE$.
8. Given angles: $\angle A = 52^\circ$, $\angle D = 27^\circ$.
9. **Key fact:** The angle between a tangent and a chord through the point of contact equals the angle in the alternate segment.
10. Tangent $BC$ touches the circle at $B$, so $\theta$ equals the angle in the alternate segment at $A$, which is $52^\circ$.
11. **Reason:** Alternate segment theorem.
**Final answers:**
$$x = 44^\circ$$
$$\theta = 52^\circ$$
Circle Angles D0B25D
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