1. **State the problem:** We need to find the center and radius of the circle given by the equation $$(x - 3)^2 + (y + 6)^2 = 4$$. 2. **Recall the formula:** The general form of a circle's equation is $$(x - h)^2 + (y - k)^2 = r^2$$ where $(h, k)$ is the center and $r$ is the radius. 3. **Identify the center:** Comparing the given equation to the general form, we see: - $h = 3$ - $k = -6$ (because the equation has $y + 6$, which is $y - (-6)$) 4. **Find the radius:** The right side of the equation is $4$, which equals $r^2$. So, $$r = \sqrt{4} = 2$$ 5. **Final answer:** - Center: $(3, -6)$ - Radius: $2$