1. The problem is to understand the equation $$(x-3)^2 + (y-k)^2 = r^2$$ and identify its type. 2. This equation represents a circle in the coordinate plane, not a trigonometric function. 3. The general form of a circle's equation is $$(x-h)^2 + (y-j)^2 = r^2$$ where $(h,j)$ is the center and $r$ is the radius. 4. Comparing, we see the center is at $(3,k)$ and the radius is $r$. 5. This equation describes all points $(x,y)$ that are exactly $r$ units away from the center $(3,k)$. 6. There are no trigonometric functions involved here; it is purely geometric. Final answer: The equation $$(x-3)^2 + (y-k)^2 = r^2$$ is the equation of a circle with center $(3,k)$ and radius $r$.