1. **Stating the problem:** We have a circle with radius 6, and a triangle formed by a radius, a segment outside the circle labeled 8, and the hypotenuse labeled $x$. We need to find the value of $x$.
2. **Understanding the setup:** The radius is 6, and the segment outside the circle is 8, so the total length of the hypotenuse $x$ is the sum of the radius and the outside segment.
3. **Formula used:** Since the hypotenuse $x$ is the sum of the radius and the outside segment, we have:
$$x = 6 + 8$$
4. **Calculating $x$:**
$$x = 14$$
5. **Answer:** The length of the hypotenuse $x$ is 14.
Circle Hypotenuse Dd54Bc
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