1. You asked for points on the graph that are exactly five units away from the origin.
2. The distance from the origin to a point $(x,y)$ is given by the formula $$\sqrt{x^2 + y^2} = 5$$.
3. Squaring both sides, we get $$x^2 + y^2 = 25$$.
4. This is the equation of a circle centered at the origin with radius 5.
5. To find points on this circle, choose values for $x$ and solve for $y$:
- If $x=0$, then $y=\pm 5$ giving points $(0,5)$ and $(0,-5)$.
- If $x=3$, then $y=\pm \sqrt{25-9} = \pm 4$ giving points $(3,4)$ and $(3,-4)$.
- If $x=4$, then $y=\pm \sqrt{25-16} = \pm 3$ giving points $(4,3)$ and $(4,-3)$.
- If $x=5$, then $y=0$ giving point $(5,0)$.
- If $x=-5$, then $y=0$ giving point $(-5,0)$.
6. These points are exactly five units from the origin on the graph.
Circle Points 649Ab5
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.