1. **Stating the problem:** Calculate the area of the shaded triangle in the figure labeled 3. 2. **Understanding the problem:** The problem involves a triangle with some given dimensions or related areas. Since the user only asked for problem 3, and no direct data is given in the text for problem 3, we must infer from the table that the circle's circumference is 32 cm. 3. **Formula for circumference of a circle:** $$ C = 2 \pi r $$ where $C$ is the circumference and $r$ is the radius. 4. **Calculate the radius:** Given $C = 32$ cm and $\pi \approx 3.14$, solve for $r$: $$ 32 = 2 \times 3.14 \times r $$ Divide both sides by $2 \times 3.14$: $$ r = \frac{32}{2 \times 3.14} $$ Show cancellation: $$ r = \frac{32}{\cancel{2} \times 3.14} = \frac{32}{6.28} $$ Calculate: $$ r \approx 5.10 \text{ cm} $$ 5. **Calculate diameter:** $$ d = 2r = 2 \times 5.10 = 10.20 \text{ cm} $$ 6. **Calculate area of the circle:** Formula for area: $$ A = \pi r^2 $$ Calculate: $$ A = 3.14 \times (5.10)^2 = 3.14 \times 26.01 = 81.63 \text{ cm}^2 $$ 7. **Summary:** - Radius $r \approx 5.10$ cm - Diameter $d \approx 10.20$ cm - Circumference $C = 32$ cm (given) - Area $A \approx 81.63$ cm² Since the problem 3 in the table is about circle properties, this completes the calculation. **Final answer:** Radius $r \approx 5.10$ cm, Diameter $d \approx 10.20$ cm, Area $A \approx 81.63$ cm².