1. **Stating the problem:** We need to calculate the arc length and area of a circle sector with radius $r=16$ m and central angle $\theta=140^\circ$. 2. **Formulas used:** - Arc length $s$ of a sector: $$s = r \times \theta_{rad}$$ where $\theta_{rad}$ is the central angle in radians. - Area $A$ of a sector: $$A = \frac{\theta}{360^\circ} \times \pi r^2$$ 3. **Convert angle to radians for arc length:** $$\theta_{rad} = 140^\circ \times \frac{\pi}{180^\circ} = \frac{140\pi}{180} = \frac{7\pi}{9}$$ 4. **Calculate arc length:** $$s = 16 \times \frac{7\pi}{9} = \frac{112\pi}{9} \approx 39.05\text{ m}$$ 5. **Calculate area of sector:** $$A = \frac{140}{360} \times \pi \times 16^2 = \frac{7}{18} \times \pi \times 256 = \frac{1792\pi}{18} = \frac{896\pi}{9} \approx 312.69\text{ m}^2$$ 6. **Final answers:** - Arc length $s \approx 39.05$ m - Area $A \approx 312.69$ m²