1. **Problem statement:** We have a circle with center $O$. Segments $UX$ and $UV$ are tangents to the circle, and $XV$ passes through the center $O$. Given $UV=12.6$ and $XV=12$, we need to find $XW$.
2. **Key properties and formulas:**
- Tangents from a common external point to a circle are equal in length. So, $UX = UV$.
- Since $XV$ passes through the center $O$, $XV$ is a diameter or a chord passing through the center.
- The tangent at point $W$ touches the circle, so $XW$ is a tangent segment from $X$ to the circle.
3. **Understanding the figure:**
- $UX$ and $UV$ are tangents from point $U$.
- $XV$ passes through $O$, so $O$ lies on $XV$.
- Points $U$, $X$, $W$, and $V$ are arranged such that $XW$ is a tangent segment from $X$.
4. **Using the tangent-secant theorem:**
For a point outside a circle, the square of the length of the tangent segment equals the product of the lengths of the secant segment and its external part.
Here, from point $X$, the tangent segment is $XW$, and the secant segment is $XV$ passing through $O$.
So,
$$XW^2 = XU \times XV$$
But we need to identify $XU$.
5. **Using the equality of tangents from $U$:**
Since $UX$ and $UV$ are tangents from $U$,
$$UX = UV = 12.6$$
6. **Using the tangent-secant theorem at point $X$:**
Since $XW$ is tangent and $XV$ is secant,
$$XW^2 = XU \times XV$$
Substitute known values:
$$XW^2 = 12.6 \times 12 = 151.2$$
7. **Calculate $XW$:**
$$XW = \sqrt{151.2} \approx 12.3$$
**Final answer:**
$$XW \approx 12.3$$
Circle Tangents 6133A0
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