1. **State the problem:** Find the total area of a composite figure consisting of three rectangles and one semicircle. 2. **Identify the shapes and their dimensions:** - Bottom-left rectangle: width = 8 m, height = 13 m - Middle rectangle above bottom-left: width = 9 m, height = 4 m - Top-center rectangle: width = 5 m, height = 9 m - Semicircle to the right of the middle rectangle: diameter = 11 m 3. **Formulas used:** - Area of a rectangle = width \times height - Area of a semicircle = \frac{1}{2} \pi r^2, where $r = \frac{\text{diameter}}{2}$ 4. **Calculate areas of rectangles:** - Bottom-left rectangle area = $8 \times 13 = 104$ m$^2$ - Middle rectangle area = $9 \times 4 = 36$ m$^2$ - Top-center rectangle area = $5 \times 9 = 45$ m$^2$ 5. **Calculate area of semicircle:** - Radius $r = \frac{11}{2} = 5.5$ m - Semicircle area = $\frac{1}{2} \pi (5.5)^2 = \frac{1}{2} \pi \times 30.25 = 15.125\pi$ m$^2$ 6. **Sum all areas:** $$\text{Total area} = 104 + 36 + 45 + 15.125\pi$$ 7. **Approximate using $\pi \approx 3.1416$:** $$15.125 \times 3.1416 \approx 47.49$$ $$\text{Total area} \approx 104 + 36 + 45 + 47.49 = 232.49$$ **Final answer:** The area of the figure is approximately **232.49 square meters**.