1. **State the problem:** Find the area of a composite figure consisting of a large right triangle and two rectangles. 2. **Identify the shapes and their dimensions:** - Large right triangle: base $= 18$ m, height $= 14$ m - Rectangle 1 (on top of the triangle): width $= 7$ m, height $= 4$ m - Rectangle 2 (to the right of Rectangle 1): width $= 5$ m, height $= 4$ m 3. **Formula for area:** - Area of a triangle: $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$ - Area of a rectangle: $$\text{Area} = \text{width} \times \text{height}$$ 4. **Calculate the area of the large triangle:** $$\text{Area}_{\text{triangle}} = \frac{1}{2} \times 18 \times 14 = \frac{1}{2} \times 252 = 126$$ 5. **Calculate the area of Rectangle 1:** $$\text{Area}_{\text{rect1}} = 7 \times 4 = 28$$ 6. **Calculate the area of Rectangle 2:** $$\text{Area}_{\text{rect2}} = 5 \times 4 = 20$$ 7. **Add all areas to find the total area:** $$\text{Total Area} = 126 + 28 + 20 = 174$$ **Final answer:** The area of the figure is $174$ square meters.