1. **State the problem:** Find the area of the composite figure consisting of a rectangle with dimensions 9 ft by 8 ft, a semicircle attached on the left side with diameter 8 ft, and a smaller semicircle attached on the top with diameter 6 ft. 2. **Formula and rules:** - Area of rectangle: $A_{rect} = \text{length} \times \text{width}$ - Area of a semicircle: $A_{semi} = \frac{1}{2} \pi r^2$ - Use $\pi = 3.14$ 3. **Calculate the area of the rectangle:** $$A_{rect} = 9 \times 8 = 72 \text{ ft}^2$$ 4. **Calculate the area of the left semicircle:** - Diameter = 8 ft, so radius $r = \frac{8}{2} = 4$ ft $$A_{left} = \frac{1}{2} \times 3.14 \times 4^2 = \frac{1}{2} \times 3.14 \times 16 = 25.12 \text{ ft}^2$$ 5. **Calculate the area of the top semicircle:** - Diameter = 6 ft, so radius $r = \frac{6}{2} = 3$ ft $$A_{top} = \frac{1}{2} \times 3.14 \times 3^2 = \frac{1}{2} \times 3.14 \times 9 = 14.13 \text{ ft}^2$$ 6. **Add all areas to find total area:** $$A_{total} = A_{rect} + A_{left} + A_{top} = 72 + 25.12 + 14.13 = 111.25 \text{ ft}^2$$ **Final answer:** The area of the figure is **111.25 ft²**.