1. **State the problem:** Calculate the total area of a composite shape consisting of a rectangle, a triangle, and a circle arranged as described. 2. **Formulas used:** - Area of rectangle: $A_{rect} = \text{length} \times \text{width}$ - Area of triangle: $A_{tri} = \frac{1}{2} \times \text{base} \times \text{height}$ - Area of circle: $A_{circ} = \pi \times r^2$ 3. **Calculate each area:** - Rectangle: $12 \text{ cm} \times 6 \text{ cm} = 72 \text{ cm}^2$ - Triangle: $\frac{1}{2} \times 5 \text{ cm} \times 8 \text{ cm} = 20 \text{ cm}^2$ - Circle: radius $r = \frac{12}{2} = 6 \text{ cm}$ $$A_{circ} = \pi \times 6^2 = 36\pi \text{ cm}^2$$ 4. **Sum the areas:** $$\text{Total area} = 72 + 20 + 36\pi = 92 + 36\pi \text{ cm}^2$$ 5. **Interpretation:** The total area of the composite shape is $92 + 36\pi$ square centimeters. 6. **Note:** The user also mentioned "total=12+4" which seems unrelated to the area calculation and is ignored here as it does not fit the problem context.