1. **State the problem:** Find the total area of the composite figure consisting of a rectangle on the left and a polygon on the right. 2. **Identify shapes and dimensions:** - Left rectangle: width = 8 ft, height = 6 ft - Right polygon: consists of a right triangle with base = 10 ft and height = 11 ft, plus a small rectangle on top with width = 2 ft and height = 4 ft 3. **Formulas used:** - Area of rectangle = width \times height - Area of triangle = \frac{1}{2} \times base \times height 4. **Calculate area of left rectangle:** $$\text{Area}_{left} = 8 \times 6 = 48 \text{ square feet}$$ 5. **Calculate area of small rectangle on top of right polygon:** $$\text{Area}_{small\ rectangle} = 2 \times 4 = 8 \text{ square feet}$$ 6. **Calculate area of right triangle:** $$\text{Area}_{triangle} = \frac{1}{2} \times 10 \times 11 = 55 \text{ square feet}$$ 7. **Calculate total area of right polygon:** $$\text{Area}_{right} = 55 + 8 = 63 \text{ square feet}$$ 8. **Calculate total area of the figure:** $$\text{Area}_{total} = 48 + 63 = 111 \text{ square feet}$$ **Final answer:** The total area of the figure is **111 square feet**.