1. **State the problem:** We need to find the area of the composite shape shown, which is an irregular polygon with sides labeled 9.3 cm, 2 cm, 5 cm, 4 cm, 10 cm, and 6 cm. 2. **Approach:** To find the area of an irregular polygon, we can divide it into simpler shapes such as rectangles and triangles, calculate their areas separately, and then sum them. 3. **Divide the shape:** Based on the side lengths, we can split the polygon into rectangles and right triangles by drawing horizontal and vertical lines along the given sides. 4. **Calculate areas of each part:** - Rectangle 1: length = 10 cm, width = 2 cm, area = $10 \times 2 = 20$ cm$^2$ - Rectangle 2: length = 6 cm, width = 4 cm, area = $6 \times 4 = 24$ cm$^2$ - Triangle 1 (right triangle): base = 5 cm, height = 3.3 cm (difference between 9.3 cm and 6 cm), area = $\frac{1}{2} \times 5 \times 3.3 = 8.25$ cm$^2$ 5. **Sum the areas:** $$\text{Total area} = 20 + 24 + 8.25 = 52.25 \text{ cm}^2$$ 6. **Final answer:** The area of the composite shape is **52.25 cm$^2$**.