1. **State the problem:** Find the volume of a composite shape consisting of two rectangular blocks connected by a cylindrical tube. 2. **Identify dimensions:** - Left block: $2.5\text{ cm} = 0.025\text{ m}$ (converted to meters), $1.5\text{ m}$, $1.5\text{ m}$ - Right block: $2.5\text{ cm} = 0.025\text{ m}$, $2.5\text{ m}$, $2.5\text{ m}$ - Cylinder: length (height) $h = 5\text{ m}$, diameter $D = 0.5\text{ m}$, radius $r = \frac{D}{2} = 0.25\text{ m}$ 3. **Formulas:** - Volume of rectangular block: $V = l \times w \times h$ - Volume of cylinder: $V = \pi r^2 h$ 4. **Calculate volumes:** - Left block volume: $$V_1 = 0.025 \times 1.5 \times 1.5 = 0.025 \times 2.25 = 0.05625\text{ m}^3$$ - Right block volume: $$V_2 = 0.025 \times 2.5 \times 2.5 = 0.025 \times 6.25 = 0.15625\text{ m}^3$$ - Cylinder volume: $$V_3 = \pi \times (0.25)^2 \times 5 = \pi \times 0.0625 \times 5 = \pi \times 0.3125 = 0.98175\text{ m}^3 \quad (\text{approx})$$ 5. **Add volumes for total volume:** $$V_{total} = V_1 + V_2 + V_3 = 0.05625 + 0.15625 + 0.98175 = 1.19425\text{ m}^3$$ **Final answer:** The volume of the composite shape is approximately $1.194\text{ m}^3$.