1. **State the problem:** Find the area of the given compound figure composed of two rectangles. 2. **Identify the shapes and dimensions:** - Left rectangle: height = 6 yd, width = 5 yd - Right rectangle is split into two parts: - Lower right rectangle: height = 3 yd, width = 12 yd - Upper right rectangle (step): height = 3 yd, width = 7 yd 3. **Formula for area of a rectangle:** $$\text{Area} = \text{height} \times \text{width}$$ 4. **Calculate area of left rectangle:** $$\text{Area}_1 = 6 \times 5 = 30 \text{ yd}^2$$ 5. **Calculate area of upper right rectangle:** $$\text{Area}_2 = 3 \times 7 = 21 \text{ yd}^2$$ 6. **Calculate area of lower right rectangle:** $$\text{Area}_3 = 3 \times 12 = 36 \text{ yd}^2$$ 7. **Total area:** $$\text{Total Area} = \text{Area}_1 + \text{Area}_2 + \text{Area}_3 = 30 + 21 + 36 = 87 \text{ yd}^2$$ **Final answer:** The area of the figure is **87 square yards**.