1. **Stating the problem:**
We have a cone with height 120 cm and base diameter 80 cm (thus radius 40 cm). Inside it, a cylinder is inscribed with height $h$ and radius $r$. We want to find the relationship between $h$ and $r$.
2. **Understanding the geometry:**
The cone's height is 120 cm and radius is 40 cm. The cylinder fits inside the cone, so its radius $r$ and height $h$ must satisfy the cone's linear profile.
3. **Using similar triangles:**
The radius of the cone decreases linearly from 40 cm at the base ($h=0$) to 0 at the apex ($h=120$). The radius at height $h$ is proportional to the remaining height of the cone above the cylinder.
4. **Setting up the relation:**
The radius at height $h$ is $r$, and the height from the apex to the top of the cylinder is $120 - h$.
By similar triangles:
$$\frac{r}{40} = \frac{120 - h}{120}$$
5. **Solving for $h$ in terms of $r$:**
Multiply both sides by 120:
$$120 \cdot \frac{r}{40} = 120 - h$$
Simplify:
$$3r = 120 - h$$
Rearranged:
$$h = 120 - 3r$$
6. **Interpretation:**
This formula shows that as the radius $r$ of the inscribed cylinder increases, its height $h$ decreases linearly.
**Final answer:**
$$h = 120 - 3r$$
Cone Cylinder 11B982
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