1. **State the problem:** We need to find how many truckloads are required to move a conical pile of pebbles. The pile has a height of 10 yards and a base diameter of 6 yards. Each truck holds 7.85 yd³ of pebbles. 2. **Formula for the volume of a cone:** $$V = \frac{1}{3} \pi r^2 h$$ where $r$ is the radius of the base and $h$ is the height. 3. **Calculate the radius:** The diameter is 6 yards, so the radius is half of that: $$r = \frac{6}{2} = 3 \text{ yards}$$ 4. **Calculate the volume of the cone:** $$V = \frac{1}{3} \times 3.14 \times 3^2 \times 10$$ $$V = \frac{1}{3} \times 3.14 \times 9 \times 10$$ $$V = \frac{1}{3} \times 3.14 \times 90$$ $$V = \frac{1}{3} \times 282.6$$ $$V = 94.2 \text{ yd}^3$$ 5. **Calculate the number of truckloads:** Divide the total volume by the volume each truck can hold: $$\text{truckloads} = \frac{94.2}{7.85}$$ Show intermediate cancellation: $$\text{truckloads} = \frac{\cancel{94.2}}{\cancel{7.85}} \approx 12$$ 6. **Final answer:** The company will need approximately 12 truckloads to move all the pebbles.