1. **State the problem:** Find the volume of a right circular cone with height $h=7$ yards and slant height $l=9$ yards. 2. **Recall the formula for the volume of a cone:** $$V=\frac{1}{3}\pi r^2 h$$ where $r$ is the radius of the base and $h$ is the height. 3. **Find the radius $r$ using the Pythagorean theorem:** Since the slant height $l$ is the hypotenuse of the right triangle formed by the radius $r$ and height $h$, we have $$l^2 = r^2 + h^2$$ Substitute $l=9$ and $h=7$: $$9^2 = r^2 + 7^2$$ $$81 = r^2 + 49$$ 4. **Solve for $r^2$:** $$r^2 = 81 - 49 = 32$$ 5. **Calculate the volume:** $$V = \frac{1}{3} \pi r^2 h = \frac{1}{3} \pi (32)(7) = \frac{224}{3} \pi$$ 6. **Approximate the volume:** $$V \approx \frac{224}{3} \times 3.1416 \approx 234.57$$ 7. **Round to the nearest tenth:** $$V \approx 234.6$$ cubic yards. **Final answer:** The volume of the cone is about 234.6 cubic yards.