1. **State the problem:** Find the distance between the points $(4, -4)$ and $(9, -2)$ on the coordinate plane.
2. **Formula used:** The distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the distance formula:
$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
This formula comes from the Pythagorean theorem, where the difference in $x$ and $y$ coordinates form the legs of a right triangle.
3. **Substitute the values:**
$$d = \sqrt{(9 - 4)^2 + (-2 - (-4))^2}$$
4. **Simplify inside the parentheses:**
$$d = \sqrt{5^2 + ( -2 + 4 )^2}$$
$$d = \sqrt{5^2 + 2^2}$$
5. **Calculate the squares:**
$$d = \sqrt{25 + 4}$$
6. **Add the values inside the square root:**
$$d = \sqrt{29}$$
7. **Find the decimal approximation:**
$$d \approx 5.385$$
8. **Round to the nearest tenth:**
$$d \approx 5.4$$
**Final answer:** The distance between the points $(4, -4)$ and $(9, -2)$ is approximately $5.4$ units.
Coordinate Distance Cdf685
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