1. Given that $\triangle XYZ \sim \triangle ACB$, corresponding angles are equal, so angle $B$ in $\triangle ACB$ corresponds to angle $Y$ in $\triangle XYZ$. 2. In $\triangle XYZ$, the sides are: $ZX = 14.4$, $XY = 16.5$, and hypotenuse $ZY = 21.9$. 3. Since angle $Y$ is opposite side $ZX$ and adjacent to side $XY$, we find: $$\cos B = \cos Y = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{XY}{ZY} = \frac{16.5}{21.9} \approx 0.75$$ $$\sin B = \sin Y = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{ZX}{ZY} = \frac{14.4}{21.9} \approx 0.66$$ $$\tan B = \tan Y = \frac{\text{opposite}}{\text{adjacent}} = \frac{ZX}{XY} = \frac{14.4}{16.5} \approx 0.87$$ 4. Rounded to the nearest hundredth: $$\cos B \approx 0.75$$ $$\sin B \approx 0.66$$ $$\tan B \approx 0.87$$