1. **State the problem:** We need to find the cosine of angle $S$ in a right triangle $TUS$ where the right angle is at vertex $U$.
2. **Identify the sides relative to angle $S$:**
- The side opposite angle $S$ is $TU$ with length 77.
- The side adjacent to angle $S$ is $US$ with length 36.
- The hypotenuse is the side opposite the right angle $U$, which is $TS$.
3. **Use the Pythagorean theorem to find the hypotenuse $TS$:**
$$TS = \sqrt{TU^2 + US^2} = \sqrt{77^2 + 36^2}$$
Calculate the squares:
$$77^2 = 5929, \quad 36^2 = 1296$$
Sum:
$$5929 + 1296 = 7225$$
So,
$$TS = \sqrt{7225} = 85$$
4. **Recall the cosine definition:**
$$\cos(S) = \frac{\text{adjacent side}}{\text{hypotenuse}}$$
For angle $S$, the adjacent side is $US = 36$ and the hypotenuse is $TS = 85$.
5. **Calculate cosine:**
$$\cos(S) = \frac{36}{85}$$
6. **Final answer:**
$$\boxed{\cos(S) = \frac{36}{85}}$$
Cosine Angle S 1220C2
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