1. The problem asks for the number of vertices of a 3-D shape formed by folding a given 2D net. 2. The net described is a cube net, consisting of 6 squares arranged in a cross shape. 3. A cube is a regular polyhedron with 6 faces, each a square. 4. The formula for the number of vertices $V$ of a cube is known: $V = 8$. 5. This is because each corner of the cube is a vertex where three edges meet. 6. Therefore, once the net is folded into a cube, it will have $8$ vertices. Final answer: The cube has $8$ vertices.