1. **State the problem:** Calculate the areas of faces A, B, and C on a cuboid with dimensions 2 m, 6 m, and 9 m. 2. **Identify the dimensions of each face:** - Face A: dimensions 6 m by 2 m - Face B: dimensions 9 m by 2 m - Face C: dimensions 6 m by 9 m 3. **Formula for area of a rectangle:** $$\text{Area} = \text{length} \times \text{width}$$ 4. **Calculate area of face A:** $$\text{Area}_A = 6 \times 2 = 12$$ 5. **Calculate area of face B:** $$\text{Area}_B = 9 \times 2 = 18$$ 6. **Calculate area of face C:** $$\text{Area}_C = 6 \times 9 = 54$$ 7. **Final answer:** - Area of face A is $12$ square meters. - Area of face B is $18$ square meters. - Area of face C is $54$ square meters. These areas represent the sizes of the rectangular faces on the cuboid.