1. **State the problem:** We need to find the total area of the two shaded faces of a cuboid. The cuboid has dimensions: height = 9 cm, width = 6 cm, and length = 11 cm. The shaded faces are the height-width face and the height-length face. 2. **Formula for area of a rectangle:** The area $A$ of a rectangle is given by $A = \text{length} \times \text{width}$. 3. **Calculate the area of the height-width face:** $$A_1 = 9 \times 6 = 54 \text{ cm}^2$$ 4. **Calculate the area of the height-length face:** $$A_2 = 9 \times 11 = 99 \text{ cm}^2$$ 5. **Find the total area of the two shaded faces:** $$\text{Total area} = A_1 + A_2 = 54 + 99 = 153 \text{ cm}^2$$ **Final answer:** The total area of the two shaded faces is $153$ cm$^2$.