1. **State the problem:** We need to find the volume of a shape formed by a large cuboid with a smaller cuboid removed from one corner. 2. **Identify dimensions:** - Large cuboid dimensions: length = 19 cm, width = 15 cm, height = 22 cm - Smaller cuboid dimensions removed: length = 9 cm, width = 12 cm, height = 2 cm 3. **Formula for volume of a cuboid:** $$\text{Volume} = \text{length} \times \text{width} \times \text{height}$$ 4. **Calculate volume of the large cuboid:** $$V_{large} = 19 \times 15 \times 22 = 6270 \text{ cm}^3$$ 5. **Calculate volume of the smaller cuboid removed:** $$V_{small} = 9 \times 12 \times 2 = 216 \text{ cm}^3$$ 6. **Calculate volume of the remaining shape:** $$V_{shape} = V_{large} - V_{small} = 6270 - 216 = 6054 \text{ cm}^3$$ 7. **Final answer:** The volume of the shape is **6054 cm³**.