1. **State the problem:** We need to find the volume of a shape formed by a large cuboid with a smaller cuboid removed from one of its corners. 2. **Formula for volume of a cuboid:** $$\text{Volume} = \text{length} \times \text{width} \times \text{height}$$ 3. **Calculate the volume of the larger cuboid:** Given dimensions: length = 22 cm, width = 12 cm, height = 19 cm. $$V_{large} = 22 \times 12 \times 19 = 5016 \text{ cm}^3$$ 4. **Calculate the volume of the smaller cuboid removed:** Given dimensions: length = 2 cm, width = 9 cm, height = 15 cm. $$V_{small} = 2 \times 9 \times 15 = 270 \text{ cm}^3$$ 5. **Calculate the volume of the remaining shape:** Subtract the smaller cuboid volume from the larger cuboid volume: $$V_{shape} = V_{large} - V_{small} = 5016 - 270 = 4746 \text{ cm}^3$$ **Final answer:** The volume of the shape is **4746 cm³**.