1. **Problem Statement:** Find the area of the curved surface of a cylinder with radius $r=14$ cm and height $h=36$ cm, and express the area in square meters as well. 2. **Formula Used:** The curved surface area (CSA) of a cylinder is given by: $$\text{CSA} = 2\pi rh$$ where $r$ is the radius and $h$ is the height. 3. **Calculation in cm:** Substitute $r=14$ cm and $h=36$ cm: $$\text{CSA} = 2 \times \pi \times 14 \times 36$$ $$= 2 \times 3.1416 \times 14 \times 36$$ $$= 2 \times 3.1416 \times 504$$ $$= 2 \times 1583.36 = 3166.72 \text{ cm}^2$$ 4. **Convert to square meters:** Since $1 \text{ m} = 100 \text{ cm}$, then $$1 \text{ m}^2 = 100 \times 100 = 10,000 \text{ cm}^2$$ So, $$3166.72 \text{ cm}^2 = \frac{3166.72}{10,000} = 0.316672 \text{ m}^2$$ 5. **Final Answer:** The curved surface area is: $$3166.72 \text{ cm}^2 = 0.316672 \text{ m}^2$$