1. **State the problem:** We need to find how much more water the cylinder can hold compared to the cone. Both have radius $r=5$ inches and height $h=12$ inches. 2. **Formulas:** - Volume of a cylinder: $$V_{cyl} = \pi r^2 h$$ - Volume of a cone: $$V_{cone} = \frac{1}{3} \pi r^2 h$$ 3. **Calculate the volume of the cylinder:** $$V_{cyl} = \pi \times 5^2 \times 12 = \pi \times 25 \times 12 = 300\pi$$ 4. **Calculate the volume of the cone:** $$V_{cone} = \frac{1}{3} \pi \times 5^2 \times 12 = \frac{1}{3} \pi \times 25 \times 12 = 100\pi$$ 5. **Find the difference:** $$V_{diff} = V_{cyl} - V_{cone} = 300\pi - 100\pi = 200\pi$$ 6. **Approximate the difference:** Using $\pi \approx 3.1416$, $$200\pi \approx 200 \times 3.1416 = 628.3$$ **Answer:** The cylinder can hold approximately 628.3 cubic inches more water than the cone, rounded to the tenths place.