1. **Problem:** The curved surface area (CSA) of a right circular cylinder of height 14 cm is 88 cm². Find the diameter of the base of the cylinder. 2. **Formula:** The curved surface area of a cylinder is given by $$\text{CSA} = 2 \pi r h$$ where $r$ is the radius and $h$ is the height. 3. **Given:** $h = 14$ cm, $\text{CSA} = 88$ cm². 4. **Step 1:** Substitute the known values into the formula: $$88 = 2 \pi r \times 14$$ 5. **Step 2:** Simplify the right side: $$88 = 28 \pi r$$ 6. **Step 3:** Solve for $r$: $$r = \frac{88}{28 \pi}$$ 7. **Step 4:** Simplify the fraction: $$r = \frac{\cancel{88}}{\cancel{28} \pi} = \frac{22}{7 \pi}$$ 8. **Step 5:** Use $\pi \approx \frac{22}{7}$: $$r = \frac{22}{7 \times \frac{22}{7}} = 1 \text{ cm}$$ 9. **Step 6:** Diameter $d = 2r = 2 \times 1 = 2$ cm. **Final answer:** The diameter of the base of the cylinder is 2 cm.