1. **State the problem:** We need to find the surface area of a cylindrical soup can with radius $AB = 2.7$ cm and height $BC = 10.9$ cm. 2. **Formula for surface area of a cylinder:** $$\text{Surface Area} = 2\pi r^2 + 2\pi r h$$ where $r$ is the radius and $h$ is the height. 3. **Given values:** - Radius $r = 2.7$ cm - Height $h = 10.9$ cm - Use $\pi \approx 3.14$ 4. **Calculate the area of the two circular bases:** $$2\pi r^2 = 2 \times 3.14 \times (2.7)^2$$ $$= 2 \times 3.14 \times 7.29 = 2 \times 22.8906 = 45.7812$$ 5. **Calculate the lateral surface area:** $$2\pi r h = 2 \times 3.14 \times 2.7 \times 10.9$$ $$= 2 \times 3.14 \times 29.43 = 2 \times 92.4102 = 184.8204$$ 6. **Add the two areas to get total surface area:** $$\text{Surface Area} = 45.7812 + 184.8204 = 230.6016$$ 7. **Final answer:** The surface area of the can is approximately **230.60 square centimeters**.