1. **State the problem:** We need to find the volume of a cylindrical can with radius $r = 3.6$ cm and height $h = 10$ cm. 2. **Formula for volume of a cylinder:** The volume $V$ is given by $$V = \pi r^2 h$$ where $r$ is the radius and $h$ is the height. 3. **Substitute the values:** $$V = \pi \times (3.6)^2 \times 10$$ 4. **Calculate the square of the radius:** $$3.6^2 = 12.96$$ 5. **Calculate the volume:** $$V = \pi \times 12.96 \times 10 = 129.6 \pi$$ 6. **Use the approximation $\pi \approx 3.1416$ to find the numerical value:** $$V \approx 129.6 \times 3.1416 = 406.92$$ 7. **Final answer:** The volume of the can is approximately $$\boxed{406.92 \text{ cm}^3}$$