1. **State the problem:** We need to find the volume of a cylindrical grain silo with diameter 16 ft and height 43 ft. 2. **Formula for volume of a cylinder:** $$V = \pi r^2 h$$ where $r$ is the radius and $h$ is the height. 3. **Calculate the radius:** The radius $r$ is half the diameter: $$r = \frac{16}{2} = 8 \text{ ft}$$ 4. **Substitute values into the formula:** $$V = 3.14 \times 8^2 \times 43$$ 5. **Calculate the square of the radius:** $$8^2 = 64$$ 6. **Calculate the volume:** $$V = 3.14 \times 64 \times 43$$ 7. **Multiply step-by-step:** $$3.14 \times 64 = 200.96$$ $$200.96 \times 43 = 8639.28$$ 8. **Round to the nearest whole number:** $$V \approx 8639 \text{ ft}^3$$ **Final answer:** The volume of the silo is approximately **8639 ft³**.